Hi

you can use Job#setNumReduceTasks(int tasks) method to set the number of
reducer to output.
On Wed, Mar 13, 2013 at 2:15 PM, Vikas Jadhav <[EMAIL PROTECTED]>wrote:

> Hello,
>
> As by default Hadoop framework can shuffle (key,value) pair to only one
> reducer
>
> I have use case where i need to shufffle same (key,value) pair to multiple
> reducers
>
> Also I  willing to change the code of hadoop framework if Necessory.
>
>
> Thank you
>
> --
> *
> *
> *
>
> Thanx and Regards*
> * Vikas Jadhav*
>

--
Don't Grow Old, Grow Up... :-)

Hi
I am specifying requirement again with example.

I have use case where i need to shufffle same (key,value) pair to multiple
reducers
For Example  we have pair  (1,"ABC") and two reducers (reducer0 and
reducer1) are there then

by default this pair will go to reduce1 (cause  (key % numOfReducer) (1%2) )
how i should shuffle this pair to both reducer.

Also I willing to change the code of hadoop framework if Necessory.

 Thank you

On Wed, Mar 13, 2013 at 12:51 PM, feng lu <[EMAIL PROTECTED]> wrote:

> Hi
>
> you can use Job#setNumReduceTasks(int tasks) method to set the number of
> reducer to output.
>
>
> On Wed, Mar 13, 2013 at 2:15 PM, Vikas Jadhav <[EMAIL PROTECTED]>wrote:
>
>> Hello,
>>
>> As by default Hadoop framework can shuffle (key,value) pair to only one
>> reducer
>>
>> I have use case where i need to shufffle same (key,value) pair to
>> multiple reducers
>>
>> Also I  willing to change the code of hadoop framework if Necessory.
>>
>>
>> Thank you
>>
>> --
>> *
>> *
>> *
>>
>> Thanx and Regards*
>> * Vikas Jadhav*
>>
>
>
>
> --
> Don't Grow Old, Grow Up... :-)
>

--
*
*
*

Thanx and Regards*
* Vikas Jadhav*

Do you want the pair to go to both reducers or do you want it to go to only
one but in a random fashion ?

AFAIK, 1st is not possible. Someone on the list can correct if I am wrong.
2nd is possible by just implementing your own partitioner which randomizes
where each key goes (not sure what you gain by that).

On Wed, Mar 13, 2013 at 1:59 AM, Vikas Jadhav <[EMAIL PROTECTED]>wrote:

>
> Hi
> I am specifying requirement again with example.
>
>
>
> I have use case where i need to shufffle same (key,value) pair to multiple
> reducers
>
>
> For Example  we have pair  (1,"ABC") and two reducers (reducer0 and
> reducer1) are there then
>
> by default this pair will go to reduce1 (cause  (key % numOfReducer) > (1%2) )
>
>
> how i should shuffle this pair to both reducer.
>
> Also I willing to change the code of hadoop framework if Necessory.
>
>  Thank you
>
> On Wed, Mar 13, 2013 at 12:51 PM, feng lu <[EMAIL PROTECTED]> wrote:
>
>> Hi
>>
>> you can use Job#setNumReduceTasks(int tasks) method to set the number of
>> reducer to output.
>>
>>
>> On Wed, Mar 13, 2013 at 2:15 PM, Vikas Jadhav <[EMAIL PROTECTED]>wrote:
>>
>>> Hello,
>>>
>>> As by default Hadoop framework can shuffle (key,value) pair to only one
>>> reducer
>>>
>>> I have use case where i need to shufffle same (key,value) pair to
>>> multiple reducers
>>>
>>> Also I  willing to change the code of hadoop framework if Necessory.
>>>
>>>
>>> Thank you
>>>
>>> --
>>> *
>>> *
>>> *
>>>
>>> Thanx and Regards*
>>> * Vikas Jadhav*
>>>
>>
>>
>>
>> --
>> Don't Grow Old, Grow Up... :-)
>>
>
>
>
> --
> *
> *
> *
>
> Thanx and Regards*
> * Vikas Jadhav*
>

Use can use Custom Partitioner for that same.

Regards,

Samir.
On Wed, Mar 13, 2013 at 2:29 PM, Vikas Jadhav <[EMAIL PROTECTED]>wrote:

>
> Hi
> I am specifying requirement again with example.
>
>
>
> I have use case where i need to shufffle same (key,value) pair to multiple
> reducers
>
>
> For Example  we have pair  (1,"ABC") and two reducers (reducer0 and
> reducer1) are there then
>
> by default this pair will go to reduce1 (cause  (key % numOfReducer) > (1%2) )
>
>
> how i should shuffle this pair to both reducer.
>
> Also I willing to change the code of hadoop framework if Necessory.
>
>  Thank you
>
> On Wed, Mar 13, 2013 at 12:51 PM, feng lu <[EMAIL PROTECTED]> wrote:
>
>> Hi
>>
>> you can use Job#setNumReduceTasks(int tasks) method to set the number of
>> reducer to output.
>>
>>
>> On Wed, Mar 13, 2013 at 2:15 PM, Vikas Jadhav <[EMAIL PROTECTED]>wrote:
>>
>>> Hello,
>>>
>>> As by default Hadoop framework can shuffle (key,value) pair to only one
>>> reducer
>>>
>>> I have use case where i need to shufffle same (key,value) pair to
>>> multiple reducers
>>>
>>> Also I  willing to change the code of hadoop framework if Necessory.
>>>
>>>
>>> Thank you
>>>
>>> --
>>> *
>>> *
>>> *
>>>
>>> Thanx and Regards*
>>> * Vikas Jadhav*
>>>
>>
>>
>>
>> --
>> Don't Grow Old, Grow Up... :-)
>>
>
>
>
> --
> *
> *
> *
>
> Thanx and Regards*
> * Vikas Jadhav*
>

Hello Vikas!

Well you can duplicate your pair in mapper for each reducer, add reducer's
mark to keys and write a partitioner that will partition records acording
this marks.

I mean something like this:
In mapper you produce (key_r1 value) (key_r2 value) instead (key value)

But i cannot imagine why you need that.

WBR, Onuchin Artem

2013/3/13 Viral Bajaria <[EMAIL PROTECTED]>

> Do you want the pair to go to both reducers or do you want it to go to
> only one but in a random fashion ?
>
> AFAIK, 1st is not possible. Someone on the list can correct if I am wrong.
> 2nd is possible by just implementing your own partitioner which randomizes
> where each key goes (not sure what you gain by that).
>
>
> On Wed, Mar 13, 2013 at 1:59 AM, Vikas Jadhav <[EMAIL PROTECTED]>wrote:
>
>>
>> Hi
>> I am specifying requirement again with example.
>>
>>
>>
>> I have use case where i need to shufffle same (key,value) pair to
>> multiple reducers
>>
>>
>> For Example  we have pair  (1,"ABC") and two reducers (reducer0 and
>> reducer1) are there then
>>
>> by default this pair will go to reduce1 (cause  (key % numOfReducer) >> (1%2) )
>>
>>
>> how i should shuffle this pair to both reducer.
>>
>> Also I willing to change the code of hadoop framework if Necessory.
>>
>>   Thank you
>>
>> On Wed, Mar 13, 2013 at 12:51 PM, feng lu <[EMAIL PROTECTED]> wrote:
>>
>>> Hi
>>>
>>> you can use Job#setNumReduceTasks(int tasks) method to set the number of
>>> reducer to output.
>>>
>>>
>>> On Wed, Mar 13, 2013 at 2:15 PM, Vikas Jadhav <[EMAIL PROTECTED]>wrote:
>>>
>>>> Hello,
>>>>
>>>> As by default Hadoop framework can shuffle (key,value) pair to only one
>>>> reducer
>>>>
>>>> I have use case where i need to shufffle same (key,value) pair to
>>>> multiple reducers
>>>>
>>>> Also I  willing to change the code of hadoop framework if Necessory.
>>>>
>>>>
>>>> Thank you
>>>>
>>>> --
>>>> *
>>>> *
>>>> *
>>>>
>>>> Thanx and Regards*
>>>> * Vikas Jadhav*
>>>>
>>>
>>>
>>>
>>> --
>>> Don't Grow Old, Grow Up... :-)
>>>
>>
>>
>>
>> --
>> *
>> *
>> *
>>
>> Thanx and Regards*
>> * Vikas Jadhav*
>>
>
>

Hello I am not talking about custom partioner(custom partitioner is
involved but i want to write same pair for more number times)
i want it go to two reducer.
for example i have partioning attribute two dimensional
<x1,x2>

singatue     reduce
<0,0>         0
<0,1>         1
<1,0>         2
<1,1>         3

for <1,0>   it will goto reducer
for <1,null> it should goto to reducer 2 and 3
for <0,null> it should goto reducer 0 and 1

On Wed, Mar 13, 2013 at 2:32 PM, Viral Bajaria <[EMAIL PROTECTED]>wrote:

> Do you want the pair to go to both reducers or do you want it to go to
> only one but in a random fashion ?
>
> AFAIK, 1st is not possible. Someone on the list can correct if I am wrong.
> 2nd is possible by just implementing your own partitioner which randomizes
> where each key goes (not sure what you gain by that).
>
>
> On Wed, Mar 13, 2013 at 1:59 AM, Vikas Jadhav <[EMAIL PROTECTED]>wrote:
>
>>
>> Hi
>> I am specifying requirement again with example.
>>
>>
>>
>> I have use case where i need to shufffle same (key,value) pair to
>> multiple reducers
>>
>>
>> For Example  we have pair  (1,"ABC") and two reducers (reducer0 and
>> reducer1) are there then
>>
>> by default this pair will go to reduce1 (cause  (key % numOfReducer) >> (1%2) )
>>
>>
>> how i should shuffle this pair to both reducer.
>>
>> Also I willing to change the code of hadoop framework if Necessory.
>>
>>   Thank you
>>
>> On Wed, Mar 13, 2013 at 12:51 PM, feng lu <[EMAIL PROTECTED]> wrote:
>>
>>> Hi
>>>
>>> you can use Job#setNumReduceTasks(int tasks) method to set the number of
>>> reducer to output.
>>>
>>>
>>> On Wed, Mar 13, 2013 at 2:15 PM, Vikas Jadhav <[EMAIL PROTECTED]>wrote:
>>>
>>>> Hello,
>>>>
>>>> As by default Hadoop framework can shuffle (key,value) pair to only one
>>>> reducer
>>>>
>>>> I have use case where i need to shufffle same (key,value) pair to
>>>> multiple reducers
>>>>
>>>> Also I  willing to change the code of hadoop framework if Necessory.
>>>>
>>>>
>>>> Thank you
>>>>
>>>> --
>>>> *
>>>> *
>>>> *
>>>>
>>>> Thanx and Regards*
>>>> * Vikas Jadhav*
>>>>
>>>
>>>
>>>
>>> --
>>> Don't Grow Old, Grow Up... :-)
>>>
>>
>>
>>
>> --
>> *
>> *
>> *
>>
>> Thanx and Regards*
>> * Vikas Jadhav*
>>
>
>
--
*
*
*

Thanx and Regards*
* Vikas Jadhav*