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Re: order by date
I see how I misled you, sorry.  I wasn't implying that my csv data is cleanly represented in yyyy-MM-dd format.  I was just asking syntactically how to use date functions in HiveQL because I hadn't found any examples and I used yyyy-MM-dd in my example.  The dates in my csv tables are often in "American" format, month first without leading zeroes, e.g., "3/31/2012 7:00".  The lack of leading zeroes and the unsortabled date format make the dates difficult to work with.  I was thinking I could use the date functions with some other format to sort them (I guess it would be "M/d/yyyy h:mm" or something like that).

I admit, I didn't actually go to the trouble of providing the correct pattern string in my earlier post, I was focused on the HiveQL syntax in that post, not the precise date pattern given to the date function.

So yeah, I'm still trying to determine the best way to sort queries against the date-time columns.  One option is to read/write the entire tables with a date conversion to a lexicographic format.  Another option -- my original question in this thread -- was how I might use hive's date functions at the time a query is performed.

What do you think is the best way to deal with this?


On Mar 13, 2012, at 10:35 , Tucker, Matt wrote:

> I'm a bit confused.  It sounds like you're already storing your dates as strings in a 'yyyy-mm-dd' format.  In that case, you can just sort by dateColName.  There's no issue with using UNIX_TIMESTAMP() in the order by clause, as it outputs integer values.
> Most of the date functions in hive take arguments in string format, with a few functions that will translate between unix timestamps and datetime strings.
> Matt Tucker
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