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Hive, mail # user - Group by week?


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RE: Group by week?
Ashish Thusoo 2009-07-31, 13:51
Hive expects the expressions in the group by clause to be top level expressions in the select list

so

select platform, datediff('2007-12-31', pdate)/7, count....
from
group by platform, datediff('2007-12-31', pdate)/7

should work. You could also put the select list into a subquery and then do a group by on top of it.

For getting numeric sorting you can do an order by CAST(month(pdate) AS INT). That will probably work for you?

Ashish
________________________________________
From: Andraz Tori [[EMAIL PROTECTED]]
Sent: Friday, July 31, 2009 4:18 AM
To: [EMAIL PROTECTED]
Subject: Group by week?

Two questions:

1. How would one group by week (instead of date or time)?

My first idea was the following:

INSERT OVERWRITE TABLE platforms_weekly select platform, count(distinct
apikey), count(1), date_add(pdate, datediff('2007-12-31', pdate) / 7)
from shairlogs group by platform, datediff('2007-12-31', pdate) / 7
but the issue is that Hive can't know there's a subcalculation that is
the same in both group part and output part.

I tried to use AS statement with group expression, but no luck there [or
maybe I didn't know how].
2. When grouping by months there seems to be a problem of getting the
proper 'yyyy-mm' as part of output columns.

Here my idea was:
INSERT OVERWRITE TABLE platforms_monthly select platform, count(distinct
apikey), count(1), concat(concat(CAST(year(pdate) as STRING), '-'),
CAST(month(pdate) as STRING)) from shairlogs group by platform,
year(pdate), month(pdate)"

But the issue is that output yyyy-mm strings are not zero-padded for
months and lexical sort then breaks on them...

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Andraz Tori, CTO
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