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Re: order by date
Is see, you store the date-time as a lexicographically sortable string.  That's fine, but I'm operating on existing csv tables.  I guess I could whip up a hadoop job to convert all the date-time columns to lexicographic strings and then wrap hive around the resulting converted tables.  I was just wondering if there was a more direct approach, whether I could apply hive to the original csv tables.

*Would* the date functions work in the way I suggested in my first post or do you think a lexicographic conversion is practically required to perform date-ordering on query results?

On Mar 13, 2012, at 09:49 , Tucker, Matt wrote:

> Hi Keith,
> We generally store date columns as a string in a similar format to ISO 8601 (yyyy-mm-dd hh:MM:ss).  This way, when we put the date column in the ORDER BY clause, it will be sorted chronologically.  It also saves us the trouble of whipping out a unix timestamp calculator to figure out what we're looking at.
> There is supposed to be a TIMESTAMP data type in Hive 0.8, but I haven't found any documentation on it yet.
> Matt Tucker
> -----Original Message-----
> From: Keith Wiley [mailto:[EMAIL PROTECTED]]
> Sent: Tuesday, March 13, 2012 12:45 PM
> Subject: order by date
> I realize that hive doesn't have a date type for the columns and I realize that hive *does* have various date functions.  I just haven't found a concrete example of how these two issues are brought together.  Ordering the results of a sql query is done by adding "order by dateColName" to the query.  Are the date functions supposed to be used in the form "order by UNIX_TIMESTAMP(dateColName, 'yyyy-MM-dd')"?  Does the function just go right into the "order by" clause like that or is that totally wrong?
> How does one order query results by a date column?  Am I on the right track?
> Thanks.
Keith Wiley     [EMAIL PROTECTED]     keithwiley.com    music.keithwiley.com

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